c^2=35^2+12^2

Solution for c^2=35^2+12^2 equation:

c^2=35^2+12^2

We move all terms to the left:

c^2-(35^2+12^2)=0

We add all the numbers together, and all the variables

c^2-1369=0

a = 1; b = 0; c = -1369;
Δ = b2-4ac
Δ = 02-4·1·(-1369)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-74}{2*1}=\frac{-74}{2}
=-37
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+74}{2*1}=\frac{74}{2}
=37
$